1.

A thin wire in the form of equilateral triangle of side 31.4 cm is bent into ring the diameter of the ring is

Answer»

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1 DM = 10 cm.

Side of equilateral triangle = 31.4 dm = 314 cm

PERIMETER = 3 ( 314) = 942 cm.

GIVEN, πd = 942 cm

πd = 942cm

d = 942 / 3.14

d = 300 cm...

d = 3m ..

Hope helped!



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