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A thin wire in the form of equilateral triangle of side 31.4 cm is bent into ring the diameter of the ring is |
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Answer» rong> 1 DM = 10 cm.Side of equilateral triangle = 31.4 dm = 314 cmPERIMETER = 3 ( 314) = 942 cm.GIVEN, πd = 942 cmπd = 942cmd = 942 / 3.14d = 300 cm...d = 3m ..Hope helped!
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