1.

A thin uniform ring of mass 5 kg and radius 0.2 metre is making 2100 r.p.m. about its central axis. Its moment of inertia and kinetic energy of rotation is :

Answer»

`0.2kgm^(2),4836J`
`0.4kgm^(2),3648J`
`0.02kgm^(2),3936J`
`0.04kgm^(2),8436J`

SOLUTION :Here M.I. = `MR^(2)`
K.E. = `(1)/(2)Iomega^(2)`
Substitute and calculate


Discussion

No Comment Found

Related InterviewSolutions