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(a)The rate constants of a reaction at 500 K and 700 K are 0.02 s^(-1) and 0.07 s^(-1) respectively. Calculate the value of Ea. (b) Under what condition a bimolecular reaction behaves kinetically first order reaction ? |
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Answer» SOLUTION :(a)Accordingtoarrheniusequation `log(K_2) /(k_1) =(E_(Act ))/( 2.303 R) [(T_2 -T_1)/(T_1 T_2)]` `(K_2)/(K_1) = ( 0.07 )/( 0.02)=7/2` `T_2 = 70 K` `T_1 = 500 K` `R=8.314JK^(-1) Mol^(-1)` ` thereforelog (7)/(2)= (E_(a))/(2.303 xx (8.314 )/( 1000 ) )[ (700 -500 )/( 700 xx 500 )]` `E_a= log(7 )/(2)xx ( 2.303 xx 8.314 )/( 1000 ) xx (7000 xx 500 )/( 200 )` `=( 0.5441 xx 2.303 xx 8.314 xx 700 xx 500)/( 1000 xx 200 )` `=18.23 KJ mol^(-1)` (b)Thisis possibleonlywhen theone of the reactionis PRESENT inlargeexcess . |
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