a tennis ball is thrown up and reaches at a height of 6.05m before com

1.	a tennis ball is thrown up and reaches at a height of 6.05m before coming down what is it's initial velocity how much tot time will take to come down (assume g=10m/s)
Answer» Answer: Initial velocity of the ball is 11 m/s and TIME taken to COME down is 1.1 s EXPLANATION: HEIGHT reached by the ball is S= 6.05 m Final velocity is zero From the equation of motion $v^2 = u^2+2gS\\0=u^2+2\times -10 \times 6.05\\u=\sqrt{121} \\u=11 m/s$ Initial velocity of the ball is 11 m/s Time taken to come down is $v =u+at\\11= 10 \times t\\t= 1.1 s$ Time taken to come down is 1.1 s

a tennis ball is thrown up and reaches at a height of 6.05m before coming down what is it's initial velocity how much tot time will take to come down (assume g=10m/s)

Answer»

Answer:

Initial velocity of the ball is 11 m/s and TIME taken to COME down is 1.1 s

EXPLANATION:

HEIGHT reached by the ball is S= 6.05 m

Final velocity is zero

From the equation of motion

$v^2 = u^2+2gS\\0=u^2+2\times -10 \times 6.05\\u=\sqrt{121} \\u=11 m/s$

Initial velocity of the ball is 11 m/s

Time taken to come down is

$v =u+at\\11= 10 \times t\\t= 1.1 s$

Time taken to come down is 1.1 s

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a tennis ball is thrown up and reaches at a height of 6.05m before coming down what is it's initial velocity how much tot time will take to come down (assume g=10m/s)​

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a tennis ball is thrown up and reaches at a height of 6.05m before coming down what is it's initial velocity how much tot time will take to come down (assume g=10m/s)