A tennis ball is thrown up and reaches a height of 4.05m before coming down. What was its initial velocity ?How much total time will it take to come down ?(Assume g=10m/s²)

A tennis ball is thrown up and reaches a height of 4.05m before comi

1.	A tennis ball is thrown up and reaches a height of 4.05m before coming down. What was its initial velocity ?How much total time will it take to come down ?(Assume g=10m/s²)
Answer» ement (s) = 4.05 mg = -10 m/s² Final velocity (v) = 0 m/sTo find: Initial velocity (u) = ? Total (t) = ?Formulae: v² = u² + 2gs, u + gtTotal = 2 × tSolution: v² = u² + 2gs0² = u² + 2 × (-10) × 4.050 = u² - 81u² = 81u = 9 m/sv = u + gt0 = 9 + (-10) × t10 t = 9T = 0.9 sTime of ascent = TIME of descent ttotal = 2T= 2 × 0.9 = 1.8 sThe initial velocity was 9 m/s and total time taken to come down, is 1.8 s.

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A tennis ball is thrown up and reaches a height of 4.05m before coming down. What was its initial velocity ?How much total time will it take to come down ?(Assume g=10m/s²)​

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A tennis ball is thrown up and reaches a height of 4.05m before coming down. What was its initial velocity ?How much total time will it take to come down ?(Assume g=10m/s²)