1.

A teacher bought 40 calculators at $8.20 each and a number of other calculator costing $2.95 each. In all he spent $387. How many of the cheap calculators did he buy?

Answer»

Let N be the NUMBER of cheaper CALCULATORS. Then

n*2.95 + 40*8.20 = 387

n*2.95 = 387 - 40*8.20

n = (387 - 40*8.20)/2.95

n = 20

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