1.

A tap is situated 5m above from ground level water drops is falling regular time interval drops are falling in a such way that when first drop toches the ground 3rd drop just leave the tap at that time what is the height of 2nd drop from the tap

Answer»

Hey friend here is UR solution..

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initial velocity of each drops=0m/s

HENCE at height of 5 m it takes a TIME ' t'

Hence ½gt² = 5

or 10*t²=10

or t²=10/10

or t=1

since first drop toches
the ground when 3RD drop just leave

time interval between consecutive
drops = ½sec

hence distance traveled by 2nd drop from tap

=½*10*(½)²

= 10/8

= 1.25 meter from tap...



Hence when third drop just to left

the second drop

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HOPE this will help you...


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