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A tansmitting antenna at the top of a tower has a height 32 m and that of the receiving antenna is 50 m. What is the maximum distance between them for satisfactory communication in line of sight mode ? Given radius of earth is `6.4 xx 10^(6) m`.A. 45.5 kmB. 40.5 kmC. 35 kmD. 32 km |
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Answer» Correct Answer - A `h_T`=32 m , `h_"Receiver"`=100 m `d_"max"=sqrt(2Rh_T) + sqrt(2Rh_"Receiver")` `=sqrt(2xx64xx10^5xx32)+sqrt(2xx64xx10^5xx50)` `=64xx10^2xxsqrt10+8xx10^3xxsqrt10` `=144xx10^2 sqrt10` =`45.5 xx 10^3` = 45.5 Km |
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