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A tank is filled up to a height `2H` with a liquid and is placed on a platform of height `H` from the ground, the distance x from the ground where a small hole is punched to get the maximum range R is .A. `H`B. `1.25H`C. `1.5H`D. `2H` |
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Answer» Correct Answer - C As `x=1/2"gt"^(2)implies t=sqrt((2x)/r)` velocity of efflux `v=sqrt(2g(H-x))` Hence `R=vt=2sqrt(x(3H-x))` For range to be maximum `(dR)/(dx)=0` which gives `x=3/2H` Alternatively : Maximum range is also equal to average of two heights `x=(H+2H)/2=(3H)/2` |
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