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A tank having cross-section 'A' is filled with water upto height h_(1). What will be the time taken by water to come out of a hole of cross-section 'a' at the bottom to decrease the level from h_(1) to h_(2)· |
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Answer» A. a . `sqrt(2g).(h_(1) -h_(2))` `=pirh^(2)dg,` `A(-(du)/(dt))=av=asqrt(2gh)` or `(dh)/(dt)=-a/A(2gh)^(1//2)` `(h_(2))/(h_(1))(dh)/((h)^(1//2))=a/Asqrt(2g)_(0)^(t)dt` or `-2[sqrth]_(h_(1))^(h_(2))=a/Asqrt(2gt)` `thereforet=2[sqrt(h_(1))-sqrt(h_(2))]A/axx1/(sqrt(2g))` `=A/asqrt(2/g)[sqrt(h_(1))-sqrt(h_(2))]` `therefore` Correct choice is (b). |
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