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A tank contains ethyl alcohol of refraction index 1.35. The depth of alcohol is 308 cm. A plane mirror is placed horizontally at a depth of 154 cm in it. An object is placed 254 mm above the mirror. Calculate the apparent depth of the image formed by the mirror. |
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Answer» Solution :DEPTHOF the MIRROR = 1.54 m, OBJECT distance from the mirror = 0.254 m The image of the object is formed at a distance of 0.254 m behind the mirror. So the real depth of the image = 1.54 + 0.254 = 1.794 m `THEREFORE` Apparent depth of the image ` = ("real depth")/(MU) = (1.794)/(1.35) = 1.33m` |
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