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A tank contain two layers of liquids, water (p= 1000 kg /m3) and mercury (p= 13600 kg / m3) . A cube with the edges of length 0.3 m and having the mass of 100 kg is lowered into the tank. Describe the position of cube when it reaches the equilibrium​

Answer»

librium position 0.24 m of its height is in water while 0.6 m of its height is in mercury.Explanation:As shown in the figure LET us assume that in equilibrium condition x m of the cube lies in waterLength of the cube in Mercury = 0.3-xFrom the CONCEPT of buoyancyWeight of the cube = Buoyant Force on the cube due to water + Buoyant force on the cube due to Mercury mTherefore, length of the cube in mercury mHence in equilibrium position 0.24 m of its height is in water while 0.6 m of its height is in mercury.Hope this answer is helpful.Know More:Q: TWO bodies are in equilibrium in water from the arms of a balance the mass of a body is 36g and DENSITY is 9g/cm if the mass of other is 48 kg its density in g/cm is:Click Here: brainly.in/question/1919946Q: A mixture CONTAINING two liquids visibly separated, is placed in a separating funnel. answer the following1.what type of liquids from the mixture2.which of the liquids will form the lower layer.3.what is the principle behind this method of separationClick Here: brainly.in/question/1452278



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