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A tank can be filled by tap A in 3 hrs and B can fill it in 4 hrs. Tap C can empty this filled tank in 6 hrs. If all three taps are opened simultaneously, how long will it take to fill the tank completely?1. 8 hrs2. \(\frac{{10}}{7} hrs\)3. 5 hrs4. \(\frac{{12}}{5} hrs\) |
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Answer» Correct Answer - Option 4 : \(\frac{{12}}{5} hrs\) Given: Time taken by tap A to fill the tank = 3hrs Time taken by tap B to fill the tank = 4hrs Time taken by tap C to empty the tank = 6hrs Calculation: Amount of tank filled by A in 1hr = 1/3 Amount of tank filled by B in 1hr = 1/4 Amount of tank emptied by C in 1hr = –1/6 Amount of tank filled by A, B and C in 1hr = 1/3 + 1/4 – 1/6 ⇒ (4 + 3 – 2)/12 = 5/12 ∴ Together they will take 12/5 days to fill the tank |
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