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A tangent to the parabola y2 = 8x makes an angle of 45° with the straight line y = 3x+5. Find theequation of the tangent and its point of contact.3. |
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Answer» tan45 = |3 – m|/|1 + 3m| = 1/root2 solvinf for m we get, m = ½. TANGENT OF parabola = > 2ydy/dx = 8 dy/dx = 4/y1 |let x1 and y1 be the point of contact] m = 4/y1 = ½ y1 = 8. x1 = 64/8 = 8 the eqn. from point of contact (8,8) and slope = ½. (y – 8) = 0.5(x -8) y = x/2 + 4 is the required eqn. |
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