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A takes 8 days more than'b' to complete a certain work.If both of them together can complete 90% of the work in 16 days.then find the time taken by 'B' to complete the whole work alone?? |
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Answer» ong>Answer: Let the time taken by B working alone = X days, So, time taken by A working alone = (x + 8) days ∵ A complete 75% of the work, So, the day he will work = 75% of (x+8) = 75(x+8)/100=3(x+8)/4 B has to complete 25% of work, That is, days he will work = 25% of x = x/4 Since, B leaves the work 9 days before the work is finished, Days for which A worked - Days for which B worked = 9 days. 3 (x+8)/4 - x/4 = 9 (2X + 24) / 4 = 9 2x = 24 X = 6 Now, x + 8 = 6 + 8 = 14 Hence, time taken by A to finish the work alone would be 14 days. |
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