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A sysem is supplied power of 10 W. Temperature of the system becomes constant at 50^(@)C. With temperature of surrounding at 20^(@)C. When power is switched off system cools from t^(@)C to (t//m)^(@)C in one minute. The heat capacity of the system is 1200 J//^(@)C. find the limiting value of n. |
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Answer» `n ge 75` Heat lost in 1 minute = `(dQ)/(dt)xx60(J)=Q` `(dQ)/(dt) = 1/3 (t-20)` Fall in temperature=`t//n` `C = (Q)/(Delta theta) = ((1//3)xx(t-20)xx60)/((t//n))` PUTTING values, `1200=20n=(400n)/(t)` Since `t gt 0` so `20n gt 1200` `n ge 60`. |
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