1.

A sysem is supplied power of 10 W. Temperature of the system becomes constant at 50^(@)C. With temperature of surrounding at 20^(@)C. When power is switched off system cools from t^(@)C to (t//m)^(@)C in one minute. The heat capacity of the system is 1200 J//^(@)C. find the limiting value of n.

Answer»

`n ge 75`
`n ge 55`
`n ge 60`
`n ge 100`

SOLUTION :`(dQ)/(DT) = K(50-20)=10, so K=1//3`
Heat lost in 1 minute = `(dQ)/(dt)xx60(J)=Q`
`(dQ)/(dt) = 1/3 (t-20)`
Fall in temperature=`t//n`
`C = (Q)/(Delta theta) = ((1//3)xx(t-20)xx60)/((t//n))`
PUTTING values, `1200=20n=(400n)/(t)`
Since `t gt 0` so `20n gt 1200`
`n ge 60`.


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