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A swimming pool is 25 m long and 12 m wide. A single 4 m wide lane is roped off. Ismaeel swims in the 4 m wide lane. Swimming twolengths of the pool counts as one lap for Ismaeel.Kosha swims on the other side of the roped off lane,in the larger rectangular portion of the pool. A lapfor Kosha consists of swimming once around a circuitthat is 1/2 m away from each edge and 1/2 m away from the rope divider.a) How much longer is Kosha’s lap than Ismaeel’slap?b) Ismaeel and Kosha each complete ten laps.Determine how much farther than Ismaeel thatKosha swam. |
Answer» Given :Length of swimming pool = 25m Width of swimming pool = 12m Width of roped off lane = 4m To Find :a) How much longer the lap of Kosha compared to ISMAEEL. b) How much far did Ismaeel swam compared to Kosha. Solution :a)The large RECTANGULAR PART of the pool is 12−4 = 8 m wide. Since Kosha swims 8− 1 2 − 1 2 = 7 m wide and 25− 1 2 − 1 2 = 24 m long. The total distance Kosha swims in one lap is 24 + 7 + 24 + 7 = 62m. Ismaeel swims 25 + 25 = 50m in two lengths, or one lap. Thus Kosha’s lap is 62−50 = 12m longer than Ismaeel’s lap. b)In ten LAPS, Kosha swims 10×62 = 620m while , Ismaeel swims 10×50 = 500M. So Kosha swims 620−500 = 120m further. Alternatively: Since in each lap Kosha swims 12m further, in 10 laps she swims 10×12 = 120m further. |
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