1.

A swimming pool is 25 m long and 12 m wide. A single 4 m wide lane is roped off. Ismaeel swims in the 4 m wide lane. Swimming twolengths of the pool counts as one lap for Ismaeel.Kosha swims on the other side of the roped off lane,in the larger rectangular portion of the pool. A lapfor Kosha consists of swimming once around a circuitthat is 1/2 m away from each edge and 1/2 m away from the rope divider.a) How much longer is Kosha’s lap than Ismaeel’slap?b) Ismaeel and Kosha each complete ten laps.Determine how much farther than Ismaeel thatKosha swam.

Answer»

Given :

Length of swimming pool = 25m

Width of swimming pool = 12m

Width of roped off lane = 4m

To Find :

a) How much longer the lap of Kosha compared to ISMAEEL.

b) How much far did Ismaeel swam compared to Kosha.

Solution :

a)

The large RECTANGULAR PART of the pool is  12−4 = 8 m wide.

Since Kosha swims \frac{1}{2} m from the ‘edges’, Kosha swims around a rectangle that is

8− 1 2 − 1 2 = 7 m wide

and

25− 1 2 − 1 2 = 24 m long.

The total distance Kosha swims in one lap is

24 + 7 + 24 + 7 = 62m.

Ismaeel swims 25 + 25 = 50m in two lengths, or one lap.

Thus Kosha’s lap is 62−50 = 12m longer than Ismaeel’s lap.

b)

In ten LAPS, Kosha swims

10×62 = 620m

while ,

Ismaeel swims

10×50 = 500M.

So Kosha swims

620−500 = 120m further.

Alternatively:

Since in each lap Kosha swims 12m further, in 10 laps

she swims 10×12 = 120m further.



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