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A swimming pool can be filled by tap P and tap Q together in 36 minutes. If tap Q started first and stopped after 30 minutes, then the swimming pool is filled by a tap P in 40 minutes. In how much time the tap Q can fill the swimming pool alone?1. 45 minutes2. 60 minutes3. 75 minutes4. 90 minutes |
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Answer» Correct Answer - Option 4 : 90 minutes Given: A swimming pool can be filled by tap P and tap Q together in 36 minutes P open for 40 minutes and Q open for 30 minutes Concept: If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank. Calculation: Let the tap Q fill the tank in ‘a’ minutes. Part of the swimming pool filled by tap P in 1 minute = \(\frac{1}{{36}} - \frac{1}{{\rm{a}}}\) According to the question, ⇒ \({\rm{\;}}30 \times \frac{1}{{\rm{a}}}{\rm{}} + {\rm{}}40{\rm{}}\left( {\frac{1}{{36}} - \frac{1}{{\rm{a}}}} \right){\rm{\;}} = {\rm{}}1\) ⇒ \(\frac{{30}}{{\rm{a}}}{\rm{}} + {\rm{}}\frac{{10}}{9} - \frac{{40}}{{\rm{a}}}{\rm{}} = {\rm{}}1\) ⇒ \(\frac{{40}}{{\rm{a}}} - \frac{{30}}{{\rm{a}}}{\rm{}} = {\rm{}}\frac{{10}}{9} - 1\) ⇒ \(\frac{{10}}{{\rm{a}}}{\rm{}} = {\rm{}}\frac{1}{9}\) ⇒ a = 90 minutes ∴ Tap Q can fill the tank in 90 minutes. |
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