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A sum of ₹800 is in denominations of ₹10 and ₹20 if the total. Number of notes is 50,find the number of notes of each type Please answer in steps |
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Answer» let the number of $10 COINS be x then number of $20 coins = 50-x (as total no of coins 50) amount from $10 coins =$(10*x) = $10x amount from $20 coins = $(20 * (50 -x)) =$(1000 - 20X) total amount = $800 = 10x + 1000 - 20x = 800 = 1000 - 10x = 800 = 1000 - 800 = 10x = 200 = 10x = x= 200/10 x= 20 thus, no of $10 coins = 20 no of $20 coins =50-20 =30 plz mark it as brainliest |
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