1.

A sum of ₹800 is in denominations of ₹10 and ₹20 if the total. Number of notes is 50,find the number of notes of each type Please answer in steps

Answer»

let the number of $10 COINS be x

then number of $20 coins = 50-x (as total no of coins 50)

amount from $10 coins =$(10*x) = $10x

amount from $20 coins = $(20 * (50 -x)) =$(1000 - 20X)

total amount = $800

= 10x + 1000 - 20x = 800

=  1000 - 10x = 800

= 1000 - 800 = 10x

= 200 = 10x

= x= 200/10

x= 20

thus, no of $10 coins = 20

no of $20 coins =50-20 =30

plz mark it as brainliest



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