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A suitcase with measures 80 cm ×48 cm × 24 cm is to be covered witha tarpaulin cloth. How many metres of tarpaulin of width 96 cm is required to cover100 such suitcases? |
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Answer» The suitcasel = 80 cmb = 48 cm h = 24 cmtherefore,Total Surface Area = 2(lb + bh + lh)= 2 [(80*48) + (48*24) + (80 * 24)]= 2 (3840 + 1152 + 1920)= 2 * 6912= 13824 cm^2 Length of cloth required = (area of suitcase/ breadth) * 100= (13824/ 96) * 100= 144 * 100= 14400 cm= 14400 /100 m= 144 m |
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