A substance responds to the following test `:` `(a)` It gives a green precipitate with ammonia solution which dissolves in excess reagent forming deep blue solution. `(b)` it gives green precipitate with potassium cyanide solution which dissolves in excess reagent forming a yellow solution. `(c )` It gives green a reddish`-` brown`//` brown `-` borax bead test in the oxidising flame. The substance is `:`A. `Sr^(2+)` saltB. `Ni^(2+)` saltsC. `Mn^(2+)` saltsD. `Zn^(2+)` salts

A substance responds to the following test `:` `(a)` It gives a green

1.	A substance responds to the following test `:` `(a)` It gives a green precipitate with ammonia solution which dissolves in excess reagent forming deep blue solution. `(b)` it gives green precipitate with potassium cyanide solution which dissolves in excess reagent forming a yellow solution. `(c )` It gives green a reddish`-` brown`//` brown `-` borax bead test in the oxidising flame. The substance is `:`A. `Sr^(2+)` saltB. `Ni^(2+)` saltsC. `Mn^(2+)` saltsD. `Zn^(2+)` salts
Answer» Correct Answer - 2 `(a)Ni^(2+)+2NH_(3)+2H_(2)OrarrNi(OH)_(2) darr ("green")+2NH_(4)^(+)` `Ni(OH)_(2)darr+6NH_(3)rarr[Ni(NH_(3))_(6)]^(2+)("deep blue")+2OH^(-)` `(b)Ni^(2+)+2CN^(-)rarrNi(CN)_(2)darr("green")` `Ni(CN)_(2)+2CN^(-)rarr [Ni(CN)_(4)]^(2-)("yellow")` `(c )Ni(BO_(2))_(2)-` reddish brown or brown borax bead in oxidising flame.

Discussion

No Comment Found

Related InterviewSolutions

When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N, the solution turns light blue. Addition of aqueous `NaCl` to the blue solution gives a white precipitate O. Addition of aqueous `NH_(3)` dissolves O and gives an intense blue solution. The final solution containsA. `[Pb(NH_(3))_(4)]^(2+)` and `[CoCl_(4)]^(2-)`B. `[Al(NH_(3))_(4)]^(3+)]` and `[Cu(NH_(3))_(4)]^(2+)`C. `[Ag(NH_(3))_(2)]^(+)` and `[Cu(NH_(3))_(4)]^(2+)`D. `[Ag(NH_(3))_(2)]^(+)` and `[Ni(NH_(3))_(6)]^(2+)`
`(NH_(4))_(2)Cr_(2)O_(7)` on heating gives a gas which is also given byA. Heating `NH_(4)NO_(2)`B. Heating `NH_(4)NO_(3)`C. `Mg_(3)N_(2)+H_(2)O`D. `Na(comp.)+H_(2)O`
A sodium salt on treatment with `MgCl_(2)` gives white precipitate only on heating. The anion of sodium salt isA. `HCO_(3)^(-)`B. `CO_(3)^(2-)`C. `NO_(3)^(-)`D. `SO_(4)^(2-)`
To a metal nitrate, when KI solution is added, a black precipitate is produced at first , on additing excess of KI, orange solution is produced. Identify the meatl ionA. `Hg^(2+)`B. `Bi^(3+)`C. `Cu^(2+)`D. `Pb^(2+)`
A metal nitrate reacts with `KI` to give a black precipitate which on addition of excess of `KI` convert into orange colour solution. The cation of metal nitrate isA. `Hg^(2+)`B. `Bi^(3+)`C. `Sn^(2+)`D. `Pb^(2+)`
A metal nitrate reacts with `KI` to give a black precipitate which on addition of excess of `Kl` is converted into orange colour solution.The cation of the metal nitrate is :A. `Hg^(2+)`B. `Bi^(3+)`C. `Pb^(2+)`D. `Cu^(+)`
Assertion : Change in colour of the acidic solution of breath is used as a test for drunken driver. Reason : Change in colour is due to complexation of alcohol with potassium dichromate.
`S_(1) :` Silver iodide is fairly soluble in hypo solution. `S_(2) :` Heavy metal chloride like `AgCl,HgCl_(2)` etc. also respond to Chromyl chloride test. `S_(3) :` Bromine reacts with `KI` liberating violet vapours of iodine. `S_(4) :` Diphenylamine reagent test is also given by nitrites chlorates, bromates, iodates, etc. in addition to `NO_(3)^(-)`A. `T T T F`B. `T F T T`C. `T T F F `D. `F F T T `
Statement I Sulphate is extimated as `BaSO_(4)`, not as `MgSO_(4)`. Statement II Ionic radius of `Mg^(2+)` is smaller than that of `Ba^(2+)`.
Addition of excess of sodium hydroxide solution to stannous chloride solution, we obtain:A. Al and BiB. Al and ZnC. Zn and MgD. Al,Bi and Zn

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment