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A submarine emits a sonar pulse, which returns from an underwater cliff in `1.02 s`. If the speed of sound in water is `1531 m//s`, how far away is the cliff ? |
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Answer» Time taken by the sonar pulse to return, t = 1.02 s Speed of sound in salt water, v = 1531 ms - 1 Distance of the cliff from the submarine = Speed of sound `xx` Time taken Distance of the cliff from the submarine = 1.02 `xx` 1531 = 1561.62 m Distance travelled by the sonar pulse during its transmission and reception in water = 2 `xx` Actual distance = 2d Actual Distance, d= Distance of the cliff from the submarine/2 = 1561/2 = 780.31 m |
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