1.

A submarine emits a sonar pilse, which returns from an underwater cliff in `1.02 s`. If the speed of sound in water is `1531 m//s`, how far away is the cliff ?

Answer» If `d` is the distance of the underwater cliff from the submarine, distance travelled by sonar pulse while going from the submarine and returning to it after getting reflected from the cliff `= 2 d`
Here, time taken by sonar pulse to return, `t = 1.02 s`
speed of sound in water, `v = 1531 m//s`
As total distance travelled by the sonar pulse = speed of sound xx time,
`2 d = v t`
or `d = (vt)/(2)`
i.e., `d = (1531 xx 1.02)/(0.2) = 780.81 m`.


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