1.

A submarine emits a sonal pulse, which returns from an underwater cliff in 1.02s. If the speed of sound in salt water is 1531 m/s how far away is the cliff?

Answer»

Speed of sound in sea water, v = 1531 m/s.
Distance travelled ultrasonic sound = 2 × depth sea = 2d.
Here d means depth of sea
2d = Speed of sound × time
= 1531 m/s × 1.02
= 1561.62 m
d = 1561.62/2 = 780.81 m.
Cliff is 780.81 m away from the sea.



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