Saved Bookmarks
| 1. |
A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. Find the number of choices available to him. |
|
Answer» Two cases are possible: (i) Selecting 4 out of first five questions and 6 out of remaining 8 questions ∴ Number of choices in this case = 5C4 × 8C6 = 5C1 × 8C2 = \(\frac{5\times8\times7}{1\times2}=140\) (ii) Selecting 5 out of first five questions and 5 out of remaining 8 questions. ⇒ Number of choices = 5C5 × 8C5 = 1 × 8C3 = \(\frac{5\times8\times7}{1\times2\times3}=56.\) ∴ Total number of choices = 140 + 56 = 196. |
|