1.

A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. Find the number of choices available to him.

Answer»

Two cases are possible: 

(i) Selecting 4 out of first five questions and 6 out of remaining 8 questions 

∴ Number of choices in this case = 5C4 × 8C6 = 5C1 × 8C2 = \(\frac{5\times8\times7}{1\times2}=140\) 

(ii) Selecting 5 out of first five questions and 5 out of remaining 8 questions. 

⇒ Number of choices = 5C5 × 8C5 = 1 × 8C3 = \(\frac{5\times8\times7}{1\times2\times3}=56.\) 

∴ Total number of choices = 140 + 56 = 196.



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