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A student got twice as many sums wrongas he got right. If he attended 60 sums inall, how many did he solve correctly? |
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Answer» Let take , right answer twice the wrong answer. Right answer = x wrong answer = 2x Sums = 60. so , x + 2x = 60 3x. = 60 x = 20. X represent correct answer = 20. |
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