1.

A student got twice as many sums wrongas he got right. If he attended 60 sums inall, how many did he solve correctly?

Answer»

Let take ,

right answer twice the wrong answer.

Right answer = x wrong answer = 2x

Sums = 60.

so , x + 2x = 60 3x. = 60 x = 20.

X represent correct answer = 20.



Discussion

No Comment Found