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a string of decoration light is formed by joining 22 bulbs of 12v each.when joined across 229v mains,the power consumption is found to be 26.4 w.calculate the redistance of each bulb |
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Answer» 120 Ω for 1 bulbExplanation:POWER of 22 bulbs = 26.4WVoltage of 1 bulb is 12VTherefore VOLTAGE of 22 bulbs = 12x22= 264 (voltage is added in series)Power = / R 26.4 = 264 x 264/ R R = 264 x 264 / 26.4 R = 2640 Ω for 22 bulbs Resistance of 1 bulb is 2640/22 = 120ΩHope this HELPS!!CHEERS!! |
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