1.

a string of decoration light is formed by joining 22 bulbs of 12v each.when joined across 229v mains,the power consumption is found to be 26.4 w.calculate the redistance of each bulb

Answer»

120 Ω for 1 bulbExplanation:POWER of 22 bulbs = 26.4WVoltage of 1 bulb is 12VTherefore VOLTAGE of 22 bulbs = 12x22= 264 (voltage is added in series)Power = / R 26.4    =  264 x 264/ R   R       =   264 x 264 /  26.4   R     =  2640 Ω for 22 bulbs Resistance of 1 bulb is 2640/22 = 120ΩHope this HELPS!!CHEERS!!



Discussion

No Comment Found

Related InterviewSolutions