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A string has a linear density of 8.5 x 10-3 kg/m and is under a tension of 280 N. The string is 1.8 m long, is fixed at both ends, and is vibrating in the standing wave pattern shown in the drawing. Determine the (a) speed, (b) wavelength, and (c) frequency of the traveling waves that make up the standing wave. |
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Answer» ear MASS density = 8.5 * 10^-3T = Tension = 280Nv = Velocity of wave = v = √(280/8.5 * 10^-3)v = √32941.176 = 181.5 m/sTo find the frequency and wavelength we need to know the FIGURE but the figure is not GIVEN here HOPE this is helpful to you PLS mark as brainliest Follow me and I'll follow you back |
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