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A stream of water flowing horizontally with a speed of 15 ms-1 gushes out of a tube of cross-sectional area 10-2 m2 and hits a vertical wall nearby. What is the force exerted on the wall by the Impact of water, assuming It does not rebound? |
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Answer» The volume of water hitting the wall per second = (Area × Velocity) of a stream of water = 10-2 × 15 = 0.15 m3s-1 density of water = 1000 kg/m3 ∴ mass of water hitting the wall per second = 0.15 × 1000= 150 kg/s Initial momentum of water hitting the wall per second = 150 × 15 = 250 kg m/s2 or 2250 N Final momentum per second = 0 ∴ Force exerted on the wall: change in momentum per second = 2250 N. |
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