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A straight wire lies along a body diagonal of an imaginary cube of side `a=20 cm,` and carries a current of 5 A (as shown in Fig. 1.61). Find the force on it due to a uniform field `vec B = 0.6 hat j T.` |
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Answer» In order to use equation `vecF=iveclxxvecB`, we would need to find the angle between `vecl and vecB`. We avoid this task by using unit vector notation. Form the problem figure, we see that `vecl=ahati-ahatj+ahatk` Thus, the force is `vecF=IveclxxvecB=IaB(hati-hatj+hatk)xx(hatj)` `=IaB(-hati+hatk)` The force lies in the xz plane and has a magnitude `F=sqrt2IaB=0.85N` |
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