1.

A straight wire carrying current I is truned intocircular loopif the magnitude of magnetic moment associated with it in is m thelength of wire will be

Answer»

`4piimn`
`sqrt {(4pim)/(i)}`
`sqrt(4pii)/(m)`
`(mpi)/(4i)`

Solution :Magneticof magnet =10 cm `=10xx10^(-2)m`
`r=15xx10^(-2) m`
`OP=sqrt(225-25)=sqrt(200)` cm
since at the neutral pointmagnetic field DUE to the magnet equal to `B_(H)`
`B_(H)=(mu_(0))/(4pi).(M)/(OP^(2)+AO^(2))^(3//2)`
`0.4xx10^(3)xx10^(-6)(225)^(3//2)=M`
`M=1.35 A-m`


Discussion

No Comment Found

Related InterviewSolutions