A stove consumes 1 gram of kerosene in 48 seconds. if the calorific value of kerosene is 48 KJ / gm, then the power of consumption of the stove in kW is

A stove consumes 1 gram of kerosene in 48 seconds. if the calorific va

1.	A stove consumes 1 gram of kerosene in 48 seconds. if the calorific value of kerosene is 48 KJ / gm, then the power of consumption of the stove in kW is
Answer» 48 KJ / GRAM * 1 gram / 48 seconds = 1 kJ / SECOND = 1 kW.