1.

a stone thrown vertically upwards with initial velocity u reaches a height 'h' before coming down. show that the Time taken to go up is same as the time taken to come down.​

Answer»

Answer:

Explanation:

When STONE throw upward with initial velocity, u

Final velocity at maximum height, v=0

Apply kinematic EQUATION of motion.

v=u+at

t=  

a

v−u

​

=  

−g

0−u

​

 

Apply kinematic equation of motion.

s=ut+  

2

1

​

at  

2

 

h=u(  

g

u

​

)−  

2

1

​

g(  

g

u

​

)  

2

 

u=  

2gh

​

 

Time,

t=  

g

u

​

=  

g

2gh

​

 

​

 

t=  

g

2h

​

 

​

.(1)

(ii) When stone DROP from height h

Apply kinematic equation of motion.

v  

2

−u  

2

=2gh

v=  u +at

2gh

​

 

Apply kinematic equation of motion.

v= t

t=  

a

v−u

​

=  

g

2gh

​

−0

​

=  

g

2h

​

 

​

(2)

From (1 ) and (2) it is proved that the time taken to GO up is same as the time taken to come down.


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