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A stone thrown vertically upward rises ‘s’ ft. in ‘t’ sec. where s = 80t – 16t2. What its velocity after 2 sec? Find the acceleration? |
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Answer» Given S = 80t -16t2 v = \(\frac{ds}{dt}\)= 80 – 32t At t = 2 sec, v = 80 – 32 (2) = 80 – 64 = 16 ft./sec. Acceleration =\(\frac{ds}{dt}\) = -22 ft/sec2. |
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