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a stone thrown upward with a speed u from the top of the tower reaches the ground with a velocity 4u.the height of the tower is |
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Answer» Height of the tower = 15u²/2gStep by step explanations :Given,a stone THROWN upward with a speed u from the top of the tower REACHES the ground with a VELOCITY 4uHere, Initial velocity of the stone = UAND we know that velocity at which is thrown upwards it passes it initial position at the same speed so, speed of stone in during passing it's initial position = uso, now we have, Initial velocity = ufinal velocity = 4uv² = u² + 2gh(4u)² = u² + 2gh2gh = 16u² - u²2gh = 15u² h = 15u²/2gso, Height of the tower = 15u²/2g |
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