1.

A stone of volume 20 cc, weighs 70 g-force in air. When the stone is fully immersed in water and weighed by spring balance, its weight is 50 g-force . At the same time 20 cc of water is displaced.(i) How much is the apparent loss of weight of stone in water?(ii) How much is the weight of water displaced by the stone?​Please I will mark Brainliest alsoPlease I will mark Brainliest alsoPlease I will mark Brainliest alsoPlease I will mark Brainliest alsoPlease I will mark Brainliest alsoPlease I will mark Brainliest alsoPlease I will mark Brainliest alsoPlease I will mark Brainliest alsoPlease I will mark Brainliest also

Answer»

The solid apparently weighs less in water when compared to AIR because of the upward buoyant force acting on it when it is SUBMERGED in water. According to Archimedes principle, the buoyant force acting on an object is equal to the WEIGHT of the fluid displaced by it. THEREFORE, the apparent decrease in the weight of an object is equal to the weight of the fluid displaced by it.Weight of displaced water = Apparent decrease in weight = 120−105=15 gfMass of displaced water = 15gVolume of solid = volume of water displaced = densitymass = 1g/cm 3 15g =15cm 3 Actual weight of solid = weight of solid in air =120gf (since buoyant force due to air is negligible)Mass of solid = 120gDensity of solid = VolumeMass = 15120 =8g/cm 3 Relative density of solid = Density water Density ssolid = 1g/cm 3 8g/cm 3 =8



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