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A stone of mass 2 kg is projected upwards with kinetic energy of 98 j the height at which the kinetic energy of the body becomes half of its original value is given by |
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Answer» where its k.e would become 49 J is H , then P.E at HEIGHT H = 98-49= 49 J = mgH , so H = 49 / (2*9.8) = 10/4 = 2.5 m |
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