1.

A stone of mass 0.5 kg is thrown with a velocity of 10 m/s across the frozen surface of a lake and it comes to rest after travelling a distance of 100 m. What is the magnitude of force of friction between the stone and ice?Choose one:3 N4 N0.25 N0.75 Ni will mark the brainliest whoever answers it fist

Answer»

We will USE the FOLLOWING equation of motion :

V² = U² - 2as

Where V is the final SPEED and u the INITIAL velocity and S is the displacement

In this case our U is 10m/s and V is 0. The S is 100.

0 = 100 - 2 × 100 × a

0 = 100 - 200a

100 = 200a

a = 0.5m/s²

Force = mass × Acceleration

Force = 0.5 × 0.5 = 0.25 N



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