A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev./min in a horizontal plane. What is the tension in the string ? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N ?

A stone of mass 0.25 kg tied to the end of a string is whirled round i

1.	A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev./min in a horizontal plane. What is the tension in the string ? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N ?
Answer» Solution :M =0.25 kgr = 1.5m = `(40 xx 2 pi)/(60) l "rad" //s` Foruniformcircularmotioncentripetal FORCE= TENSION `(mv^(2))/(R ) = T` `(0.25 xx 4pi^(2))/(1.5)= T` if200 Ntensionis provided in thestringspeedshouldbesuchthatstringdo notbreak `:. (mv^(2))/(r ) =T ` `v^(2)= (1.5 xx 200)/( 0.25) ` `:.v= 34.64 ms^(-1) `