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A stone of mass 0.12 kg is fired from a catapult. The velocity of the stone changes from 0 to 5.0 m / s in 0.60 s. What is the average resultant force acting on the stone while it is being fired? |
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Answer» Answer: 1 NEWTON Explanation: f=m(v-u)/t f=? m=0.12kg u=0m/s v=5m/s t=0.6 seconds f= 0.12(5-0)/0.6 f= 0.6/0.6 f=1 Newton 1 Newton is the FORCE |
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