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A stone is thrown vertically upwords with a velocity of 40 m /s find its position after 5 seconds |
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Answer» 80 mExplanation:Given : Initial velocity U = 40 m / secAt TOP final velocity v = 0 m / secTime t = 5 secUsing g = 10 m / sec²We are ASKED to find HEIGHT / position : Using third equation of motion : v² = u² + 2 g h= > h = ( v² - u² ) / 2 gPutting values here we GET : = > h = ( 0² - 40² ) / 2 × ( - 10 ) m= > h = - 1600 / - 20 m= > h = 160 / 2 m= > h = 80 mTherefore , required position is 80 m. |
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