a stone is thrown vertically upwards with a velocity of 40^-1 and retu

1.	a stone is thrown vertically upwards with a velocity of 40^-1 and returns back takiing g =10m^-2 calculate the maxium the height reached by the object stone and total distance traveled by the stone
Answer» Explanation: GIVEN THAT INITIAL VELOCITY= 40m/s. TO FIND MAXIMUM HEIGHT H= U²/2G SO H= 40²/20 H= 1600/20 Hmax= 80metre TOTAL DISTANCE TRAVELLED = 2×Hmax TOTAL DISTANCE TRAVELLED 2× 80 = 160 *METRE* *HOPE* IT *HELPS* *YOU* THANK YOU✌️

a stone is thrown vertically upwards with a velocity of 40^-1 and returns back takiing g =10m^-2 calculate the maxium the height reached by the object stone and total distance traveled by the stone

Answer»

Explanation:

GIVEN THAT

INITIAL VELOCITY= 40m/s.

TO FIND MAXIMUM HEIGHT

H= U²/2G

SO H= 40²/20

H= 1600/20

Hmax= 80metre

TOTAL DISTANCE TRAVELLED = 2×Hmax

TOTAL DISTANCE TRAVELLED

2× 80 = 160 METRE

HOPE IT HELPS YOU

THANK YOU✌️