1.

a stone is thrown vertically upward with an intial velocity u frok the top of a tower of height 12 u squre by g wiht what velocity does the stone reach the ground

Answer»

GIVEN: H=12u^2/g

INITIAL vel.=u

using FORMULA v^2=u^2-2as

v^2=u^2+2*g*12u^2/g (since a= -g and s=h)

so v=5u ans.




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