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a stone is thrown vertically upward with an intial velocity u frok the top of a tower of height 12 u squre by g wiht what velocity does the stone reach the ground |
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Answer» GIVEN: H=12u^2/g INITIAL vel.=u using FORMULA v^2=u^2-2as v^2=u^2+2*g*12u^2/g (since a= -g and s=h) so v=5u ans. |
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