A stone is thrown vertically upward with an initial velocity of 40 m/s . Taking the g value as 10 m/s^2 find the maximum height reached by the stone .What is the net displacement and total distance covered by the stone?

A stone is thrown vertically upward with an initial velocity of 40 m/s

1.	A stone is thrown vertically upward with an initial velocity of 40 m/s . Taking the g value as 10 m/s^2 find the maximum height reached by the stone .What is the net displacement and total distance covered by the stone?
Answer» IGHT = (U*u / 2G ) = 1600/20 = 80M

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A stone is thrown vertically upward with an initial velocity of 40 m/s . Taking the g value as 10 m/s^2 find the maximum height reached by the stone .What is the net displacement and total distance covered by the stone?

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