a stone is thrown vertically upward with a velocity of 40 metre per second and Ispat back taking degree is equal to 10 metre per second square calculate the maximum height reached by the stone what is the net displacement done Total distance covered by the sun

a stone is thrown vertically upward with a velocity of 40 metre per se

1.	a stone is thrown vertically upward with a velocity of 40 metre per second and Ispat back taking degree is equal to 10 metre per second square calculate the maximum height reached by the stone what is the net displacement done Total distance covered by the sun
Answer» EXPLANATION:v=40a=10,u=0so,from first law of motionv=u +at40=0+10[t]40/10 =t4sec=tfrom 2ND law of motions=ut+1/2ats=0[4]+1/2[10][4]s=0+20s=20m

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a stone is thrown vertically upward with a velocity of 40 metre per second and Ispat back taking degree is equal to 10 metre per second square calculate the maximum height reached by the stone what is the net displacement done Total distance covered by the sun​

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a stone is thrown vertically upward with a velocity of 40 metre per second and Ispat back taking degree is equal to 10 metre per second square calculate the maximum height reached by the stone what is the net displacement done Total distance covered by the sun