a stone is thrown vertically upward direction with a velocity of 5m/s . if the acceleration of the stone during its motion in 10m/s . in the downward direction , what will be the height attained by the stone and how much time will it take to reach there

a stone is thrown vertically upward direction with a velocity of 5m/s

1.	a stone is thrown vertically upward direction with a velocity of 5m/s . if the acceleration of the stone during its motion in 10m/s . in the downward direction , what will be the height attained by the stone and how much time will it take to reach there
Answer» $here \: is \: your \: answer$ 》Initial velcoity=u=5m/s 》acceleration=10m/s 》time{ t} =? 》MAXIMUM HEIGHT=h=? ↪using the formula , Maximum Height = Hmax $h_{max} = \frac{ {u}^{2} }{2g}$ =5x5/2x10 =5/4m =1.25m ↪Time of ascent= Time TAKEN to reach maximum height=u/g =5/10 =1/2 =0.5 SEC. $hope \: it \: helps$ $\beta e \: \beta rainly$

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a stone is thrown vertically upward direction with a velocity of 5m/s . if the acceleration of the stone during its motion in 10m/s . in the downward direction , what will be the height attained by the stone and how much time will it take to reach there

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