1.

A stone is thrown vertically upward and its velocity becomes half of its original in 15 sec. What is maximum height?

Answer»

4500 mExplanation:V = u +gtsince it is moving UPWARD G  is -ve GIVEN v=u/2and t=15u/2=gtg=10u=300 m/smaximum height =u^2/2gsubstuting the values we get height =4500m



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