A stone is thrown vertically up with an initial of 10m/s . Find the maximum height reached and the time of ascent ( take gravitational force= 10m/second square)

A stone is thrown vertically up with an initial of 10m/s . Find the ma

1.	A stone is thrown vertically up with an initial of 10m/s . Find the maximum height reached and the time of ascent ( take gravitational force= 10m/second square)
Answer» for maximum height here initial VELOCITY = 10m/s now we find TIME of ascent ,time of ascent = USIN (THETA)/g =10sin 45°/10 = 10/10 = 1s

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A stone is thrown vertically up with an initial of 10m/s . Find the maximum height reached and the time of ascent ( take gravitational force= 10m/second square)​

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A stone is thrown vertically up with an initial of 10m/s . Find the maximum height reached and the time of ascent ( take gravitational force= 10m/second square)