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a stone is thrown upward with a speed of 25m/s . another stone is simultaneously thrown downward form the same point with speed 10m/s. the relative velocity of 1st stone with respect to 2nd stone is (consider both stones are in air) |
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Answer» V1V2 = V1 - V2 = 25 - 10 = 15 Explanation:HOPE it helps youPlease Mark as BRAINLIEST |
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