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A stone is thrown upward at the speed of 20 m/s.How high will it be after 2 second?Take g=10m/s |
Answer» Given :-To Find :-
A stone is thrown up, so it MEANS it is currently going i.e it's the Initial Velocity and how much high it will go after 2 second,so we take time t and we have to find height Thus, FINDING how high the stone will go... → s = ut + ½gt² → s = 20 × 2 + ½ × 10 × (2)² → s = 40 + ½ × 10 × 4 → s = 40 + ½ × 40 → s = 40 + 20 → s = 60 Thus, the height is 60 m |
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